struct.node.link

Syntax

l = struct.node.link(sn<,i>)

Get the link associated with structure node sn. Returns null if no link is associated with the structure node.

Returns:

l - link pointer

Arguments:

sn - structure node pointer

i - Optional side indicator. Liner elements may optionally have links on two sides. If not specified this value defaults to 1, but for nodes attached to embedded liners you may also give the value 2 to specify the link on the second side.