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struct.link.find

Syntax

p = struct.link.find(i)

Get the link with internally assigned component-ID number i.

Returns:p - the pointer to the link with component-ID number i, or null if none was found
Arguments:i - a component-ID number
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⇐ struct.link.extra | struct.link.group ⇒
Was this helpful? ... PFC © 2019, Itasca Updated: Apr 26, 2019